Question

prove this question​

Answer 1

Answer:

The explanation is given below.

Step-by-step explanation:

$\frac{1-cosA}{sinA}$

= $\frac{(1+cosA)(1-cosA)}{sinA(1+cosA)}$

= $\frac{1-cos^{2}A }{sinA(1+cosA)}$

now we know

sin²A + cos²A = 1

or sin²A = 1 - cos²A

so $\frac{sin^{2}A }{sinA(1+cosA)}$

= $\frac{sinA}{1+cosA}$

[proved]

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