Math, asked by parulj438, 1 year ago

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Answered by khyati2614
9

Here is your answer

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EWAPAHUJA: it is of 9th standard
EWAPAHUJA: m I right
EWAPAHUJA: ch.10 circles ncert
parulj438: yes
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EWAPAHUJA: today was my exam of maths
Answered by devashreekadu18103
1

Answer:

Step-by-step explanation:Given: quadrilateral ABCD is a cyclic quadrilateral.

To Proove: angle B+angle D =180° angle A +angle C =180°

Proof: Arc ABC is intercepted by the inscribed angle ADC.

Therefore angle ADC=1/2 angle ADC..............(1)

Similarly,angle ABC is an inscribed angle .It intercepts arc ADC.

Therefore angle ABC=1/2m(arcADC)........(2)

Therefore measure angle ADC+angleABC =1/2 m(arcABC)+1/2 m(arcADC).........from (1) &(2)

=1/2[ m(arc ABC)+m(arcADC)]

=1/2×360°...arc ABC and arc ADC constitutes a complete circle.

=180°

Similarly we can prove,angle A +angle C = 180°.

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