Question

prove this step by step

Answer 1

The give equation is

p (n) = sin^n Q + cos^n Q

When P (6), then

P (6) = sin⁶ Q + cos⁶ Q

P (6) = (sin³Q) ² + (cos³Q) ²

As we know that,

sin²A + cos²A = 1 __________eq. 1

By applying this identity,

P (6) = 1

When P (4), then

P (4) = sin⁴Q + cos⁴Q

P (4) = (sin²Q) ² + (cos²Q) ²

By applying the eq. 1

P (4) = 1

By putting the values in equation,

= 2P (6) -3P (4) + 1
= 2 (1) - 3 (1) +1
= 2-3+1
= 1 - 1
= 0

Hence proved

Hope it will help you

Answer 2

Here is ur solution....

Hope it helps...