prove to that 1 + tan square theta upon cos square theta is equal to tan square theta
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Step-by-step explanation:your questionust be wrong it would be cot instead of cos for this
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LHS = tan²A - sin²A
= ( sin²A/cos²A ) - sin²A
= sin²A [ 1/cos²A - 1 ]
= sin²A( sec²A - 1 )
= sin²A tan²A
[ since , sec²A - 1 = tan²A ]
= tan²Asin²A
= RHS
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Step-by-step explanation:
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