Question

Prove trigonometrical identity:1+tan square a=sec square a

Answer 1

Starting From:

cos(x)^2+sin(x)^2=1

After Dividing Both sides by cos(x)^2

We Will Get,

cos(x)^2/cos(x)^2+sin(x)^2/cos(x)^2=1/cos(x)^2

1+sin(x)^2/cos(x)^2=1/cos(x)^2

So, we get,

1+Tan(x)^2=Sec(x)^2

Hence proved

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