prove velocity of efflux of a liquid is equal to the velocity of a body falling freely from surface to orifice
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H = Height of container
h = Height from the surface of the container to the orifice made
Let atmospheric pressure be P , density of liquid in tank be ρand velocity of liquid at efflux be v
Applying Bernoulli's equation at the surface of container and at the orifice we get
P+ρgH=P+12ρv2+ρg(H−h)⇒0=12ρv2−ρgh⇒12ρv2=ρgh⇒v=2gh−−−√
Thus the velocity of efflux is v=2gh−−−√
And velocity of a body falling freely has same velocity as by third equation of motion v2=0+2ghv=2gh−−−√and for range time to reach ground t=2(H−h)g−−−−−−√and range R=vt=2gh−−−√×2(H−h)g−−−−−−√=2h(H−h)−−−−−−−−√
Hope it helps!
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