Math, asked by SubodhKnautiyal, 3 months ago

prove x^0=1 please prove this

sai172982: 2³=8, 2²=4,2¹=2,2^0=1,,,,,, because every time the power increased by 1 its multiplied by 2 to follow this pattern

sai172982: same case with ur x0=1

kichu067: yes you are right

kichu067: can you follow

Answers

Answered by kichu067

Answer:

x^2*x^-2=x^0

2^2*2^-2=1

4*1/4=1

4/4=1

hence proved

Answered by Anonymous

$\huge\mathfrak{\underline{\underline{\purple{question}}}}$

$\sf \: To \: Prove:- {x}^{0}$

$\huge\mathfrak{\underline{\underline{\purple{Answer}}}}$

$\sf \: We \: know \: that \: {x}^{0} =x \times x(0 \: Times)$

$\sf \: we \: all \: know \: 1−1=0$

$\sf \: so \: we \: can \: say \: that \: {x}^{0} = {x}^{1 - 1}$

$\sf \: Now \: We \: Got \: {x}^{0} =( {x}^{1} )×({x} ^ {−1})$

$\sf \: {x}^{0} =( {x}^{1} ) \times \frac{1}{ {x}^{1 } } \: where {x}^{1} \\ \sf \: and \: {x}^{1} \: gets \: cancelled \:$

$\boxed{ \sf{\: Now \: we \: got \: {x}^{0} =1 \: Hence \: Proved}}$

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