Prove x raised to the power 0 = 1.
Solve quick plzz.
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1
hello users...
solution:-
we know that
x^( -n) = 1 / xⁿ
where, n is any real number.
now,
we can write
x^0 = x^ (1 - 1) = x^(2 - 2) = x^(n - n)
=> x^0 = x.x^(-1) = x².x^(-2) = xⁿ.x^(-n)
=> x^0 = x/x = x²/x² = xⁿ/xⁿ
=> x^0 = 1/1 = 1
hence,
proved..
✡✡ hope it helps ✡✡
solution:-
we know that
x^( -n) = 1 / xⁿ
where, n is any real number.
now,
we can write
x^0 = x^ (1 - 1) = x^(2 - 2) = x^(n - n)
=> x^0 = x.x^(-1) = x².x^(-2) = xⁿ.x^(-n)
=> x^0 = x/x = x²/x² = xⁿ/xⁿ
=> x^0 = 1/1 = 1
hence,
proved..
✡✡ hope it helps ✡✡
Answered by
0
Answer
in short, 0 is the only number such that for any number x, x + 0 = x. ... So, the reason that any number to the zero power is one is because any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1
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