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Attention: 50 points
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TheRockinCaptain:
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By using property of circle we will get
angle PAB =angle PBA
=> angle PBA =55°
and similarly ,
angleBAR=angleABR
=>angle BAR=50°
NOW, IN triangle BPQ
BY angle Sum property
25°+90°+angleBPQ=180°
angle BPQ=65°
angle PAB =angle PBA
=> angle PBA =55°
and similarly ,
angleBAR=angleABR
=>angle BAR=50°
NOW, IN triangle BPQ
BY angle Sum property
25°+90°+angleBPQ=180°
angle BPQ=65°
Answered by
1
here u are ....
hope it will help u
hope it will help u
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