Question

proved that , sin(45° + alpha) + cos(45º – alpha ) = -1/2 (cos alpha + sin alpha)​

Answer 1

Answer:

hey mate,the RHS should be √2(cos alpha+sin alpha)✔️✔️✔️

Step-by-step explanation:

refer to the attachment.

please mark it as brainlist if it helps ▪️◾◼️☑️☑️

Answer 2

$\large\boxed{Answer}$

Sin(45° + alpha) + Cos(45° - alpha)

Sin{90° - (45° - Alpha)} + Cos(45° - alpha)

Cos(45° - alpha) + Cos(45° - alpha)

2 Cos(45° - alpha)

2 {Cos45° * Cos alpha + Sin45° * Sin alpha}

2 { Cos alpha/√2 + Sin alpha/√2 }

2 (Cos alpha + Sin alpha)/√2

√2 (Cos alpha + Sin alpha)

I hope it will help u