Question

proves that disjunction distributes over conjunction?​

Answer 1

Step-by-step explanation:

I have proven using theorems that implication is left distributive over conjunction:

x→(y∧z)≡(x→y)∧(x→z)x→(y∧z)≡(x→y)∧(x→z)

Proof:

x→(y∧z)≡¬x∨(y∧z)≡(¬x∨y)∧(¬x∨z)≡(x→y)∧(x→z)

hope helpful to you ❤️ please mark has brilliant please ❤️

Answer 2

Answer:

dbhdhdhshdhshdhdhdndndbsndjdndbdjjdjddjdjjdjsjsbshs