Question

.:
Provethat root2is an irrational number.​

Answer 1

Answer:

If \sqrt 2

If \sqrt 2 2

If \sqrt 2 2

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}}

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 =

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = b

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b 

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b 

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b  =0.

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b  =0.square root of 2 is a/b such that a and b are elements of the set of integers however b cannot equal to zero

If \sqrt 2 2 is a rational number, then we can express it as a ratio of two integers.So, \sqrt 2 = {\Large{{a \over b}}} 2 = ba where aa and bb are integers but b \ne 0b  =0.square root of 2 is a/b such that a and b are elements of the set of integers however b cannot equal to zeroNow, here is the trick that makes the proof by contradiction works. We will further assume that aa and bb are relatively prime or co-prime. Two integers are said to be relatively prime if they share no common positive divisors other than 11.

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