Math, asked by chahat492, 1 year ago

prv tht: sinA-cosA+1/sinA+cosA-1=1+sinA/cosA​

Answers

Answered by insaneabhi
0

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved

Answered by Paritshith
1

Answer:

Step-by-step explanation:

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