Question

PS bisects angle P. Arrange PQ,QS,SR in their descending order of their lengths. Please solve this​

Answer 1

SR > PQ > QS

Step-by-step explanation:

In triangle PQR

∠P + ∠Q + ∠R = 180

∠P = 180 - 60- 40

∠P =  80° ------  (1)

In Δ PQS

∠PSQ = 90°, ∠PQS= 60°

∠QPS = 180 - 90 - 60

∠QPS = 30°

∠RPS = 80 - 30 = 50°

Since ∠RPS = 50°

∠QPS = 30°

∠PRQ = 40°

⇒ ∠RPS > ∠PRQ > ∠PQS

⇒ SR > PQ > QS

This is the decending order of the lengths of PQ, QS, SR.

Answer 2

Answer:

This is your answer. I hope this helps you