ps is a median of triangle PQR prove that PQ+QR+PR>2PS
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Answered by
76
Hola ^_^
Here is your answer
In ∆ PQR
1. PQ + QS > PS
【 The sum of any two sides of triangle is greater than the third side】
2. PR + RS > PS
【 The sum of any two sides of triangle is greater than the third side】
3. Therefore adding 1 and 2
PQ+ QS+ PR+ RS >2PS
PQ+ QR+ PR> 2PS
【 as QR = QS + RS】
HENCE PROVED .
Hope it helps you ^_^
Here is your answer
In ∆ PQR
1. PQ + QS > PS
【 The sum of any two sides of triangle is greater than the third side】
2. PR + RS > PS
【 The sum of any two sides of triangle is greater than the third side】
3. Therefore adding 1 and 2
PQ+ QS+ PR+ RS >2PS
PQ+ QR+ PR> 2PS
【 as QR = QS + RS】
HENCE PROVED .
Hope it helps you ^_^
Answered by
29
Answer:
Step-by-step explanation:
1. PQ + QS > PS
【 The sum of any two sides of triangle is greater than the third side】
2. PR + RS > PS
【 The sum of any two sides of triangle is greater than the third side】
3. Therefore adding 1 and 2
PQ+ QS+ PR+ RS >2PS
PQ+ QR+ PR> 2PS
【 as QR = QS + RS】
HENCE PROVED .
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