Question

ps is a median of triangle PQR prove that PQ+QR+PR>2PS

Answer 1

Hola ^_^

Here is your answer

In ∆ PQR

1. PQ + QS > PS
【 The sum of any two sides of triangle is greater than the third side】

2. PR + RS > PS
【 The sum of any two sides of triangle is greater than the third side】

3. Therefore adding 1 and 2

PQ+ QS+ PR+ RS >2PS

PQ+ QR+ PR> 2PS

【 as QR = QS + RS】

HENCE PROVED .

Hope it helps you ^_^

Answer 2

Answer:

Step-by-step explanation:

1. PQ + QS > PS

【 The sum of any two sides of triangle is greater than the third side】

2. PR + RS > PS

【 The sum of any two sides of triangle is greater than the third side】

3. Therefore adding 1 and 2

PQ+ QS+ PR+ RS >2PS

PQ+ QR+ PR> 2PS

【 as QR = QS + RS】

HENCE PROVED .