PS/SQ=PT/TR and angle PST =angle PRQ ,prove that PQR is an isosceles trinangle?
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Solution:-
It is given that PS/SQ = PT/TR
So, ST II QR (According to B.P.T)
Therefore, ∠ PST = ∠ PQR (Corresponding angles)
Also it is given that ∠ PST = ∠ PRQ
So, ∠ PRQ = ∠ PQR
Therefore, PQ = PR ( sides opposite the equal angles)
So, Δ PQR is an isosceles triangle.
Hence proved.
It is given that PS/SQ = PT/TR
So, ST II QR (According to B.P.T)
Therefore, ∠ PST = ∠ PQR (Corresponding angles)
Also it is given that ∠ PST = ∠ PRQ
So, ∠ PRQ = ∠ PQR
Therefore, PQ = PR ( sides opposite the equal angles)
So, Δ PQR is an isosceles triangle.
Hence proved.
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here is ur answer guys
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