PS²+SR²+RQ²+QP²=360°
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Answered by
1
Answer:
nP4 = 360
n! / (n-4)! = 360
n (n-1)(n-2)(n-3)(n-4)! / (n-4)! = 360
n (n-1)(n-2)(n-3) = 360
factorise 360 so that 360 can be written in the form of 4 consecutive numbers.
360 = 6×5×4×3
n (n-1)(n-2)(n-3) = 6×5×4×3
compare both L.H.S and R.H.S
therefore, n = 6
Answered by
1
Answer:
nP4 = 360
n! / (n-4)! = 360
n (n-1)(n-2)(n-3)(n-4)! / (n-4)! = 360
n (n-1)(n-2)(n-3) = 360
factorise 360 so that 360 can be written in the form of 4 consecutive numbers.
360 = 6×5×4×3
n (n-1)(n-2)(n-3) = 6×5×4×3
compare both L.H.S and R.H.S
therefore, n = 6
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