Question

Psin theta + qcos theta = root p^2+q^2
Then find the value of tan theta

Answer 1

Answer:

psin(x)+qcos(x)= root(p^2 + q^2)

dividing by cos x

psin(x)/cos(x) + q= root (p^2 + q^2))/cos(x)

ptanx=(root(p^2 +q^2))/cos(x) -q

tanx = ((root(p^2+q^2))/cos(x) -q ) p

Step-by-step explanation:

hope so this answer will give you benefit... i have replaced theta into x