Question

PT is a tangent to a circle whose Centre is if PT is 1.2 cm and PO 3.7 CM then the radius of circle is

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Answer 1

1. As according to the question,

if PT=1.2cm and PO =3.7cm,

So,

By using Pythagoras theorem,

$h {}^{2} = b {}^{2} + p {}^{2}$

So,

PT is base of a triangle .

PO is hypotenuse of a triangle .

So,

$po {}^{2} = pt {}^{2} + radius \: of \: a \: circle ^{2}$

So,

${1.2}^{2} = {3.7}^{2} + \: radius {}^{2}$

So,

radius of the given circle is,

$\sqrt{12.25} cm$