Question

Puestion 3: Two numbers are in the ratio 3:4 .If 6 is added to each term of the ratio,
There is an increase of 20 percent in the given ratio. Find the first and second number.
, 4)​

Answer 1

Answer:

I HOPE IT WILL HELPFULL FOR YOU MARK BRAIN LIST PLEASE

Step-by-step explanation:

x/y = 3/4 → 4x = 3y → 4x - 3y = 0 (1)

(x + 6)/(y + 6) = (3/4)*1,2 → (x + 6)*4 = (y + 6)*3,6 → 4x + 24 = 3,6y + 21,4 →

→ 4x - 3,6y = -2,4 (2)

By (1) - (2) we get:

0,5y = 2,4 → y = 4 and therefore x = 3

Check:

(3 +6)/(4 + 6) = 9/10 = 0,9

(3/4)*1,2 = 0,75*1,2 = 0,9

Answer 2

Step-by-step explanation:

Let the two numbers be 3x and 4x

x/y = 3/4 → 4x = 3y → 4x - 3y = 0 (1)

(x + 6)/(y + 6) = (3/4)*1,2 → (x + 6)*4 = (y + 6)*3,6 → 4x + 24 = 3,6y + 21,4 →

→ 4x - 3,6y = -2,4 (2)

By (1) - (2) we get:

0,5y = 2,4 → y = 4 and therefore x = 3

Check:

(3 +6)/(4 + 6) = 9/10 = 0,9

(3/4)*1,2 = 0,75*1,2 = 0,9

Hope it helps..

Thank You..