Question

pulling force making an angle theta to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is phi the magnetude of force required to move the body is equal to ​

Answer 1

Answer:

Answer in terms of weight

F = Wa/g cos theta + fg/g cos theta

Explanation:

Let F is the force applied

then the force in the horizontal will be F cos theta

Let F is the friction force which is acting backwards

Let m be the mass

g be the acceleration due to gravity

therefore W= mg i.e. m = W/g

now put these value in

Fcos theta - f = ma

but m = W/g

Fcos theta - f = Wa/g