Question

Puneet has a recurring deposit account in a bank and deposits 140 per month for 4
years. If he gets 78,092 on maturity, find the rate of interest given by the bank.​

Answer 1

Step-by-step explanation:

hello bro

kaise ho

aasha karta hu thik hoge

we know that

• SI=p n(n+1) r/2×12×100
• monthly deposite amount 140
• so amount of 4 years is year change in months 4×12=48 months
• 140×48=6720
• si=78092
• putting on formula
• 71372= 140×48×49×r/2×12×100
• R=71372×2×12×100/140×48×49
• 171292800/329280
• 520.20

suno bhai ye question galat hai is question ko dubara aache se post karo

Answer 2

$\underline{ \underline{{ \huge{ \mathtt{Q}}} \mathtt{UESTION -}}}$

Puneet has a Recurring Deposit account in a bank and deposits ₹ 140 per month for 4 years. If he gets ₹ 8,092 on maturity, find the rate of interest given by the bank.

$\underline{ \underline{{ \huge{ \mathtt{G}}} \mathtt{IVEN -}}}$

• Principal amount (P) = ₹ 140
• number of months (n) = 4 years to months

4 × 12 = 48 months.

• Maturity value (M.V) = ₹ 8,092

$\underline{ \underline{{ \huge{ \mathtt{T}}} \mathtt{O} \: \: \: {{ \huge{ \mathtt{F}}} \mathtt{IND -}}}}$

• Rate of interest given by the bank

$\underline{ \underline{{ \huge{ \mathtt{F}}} \mathtt{ORMULA } \: \: \: {{ \huge{ \mathtt{U}}} \mathtt{SED -}}}}$

$\underline{ \boxed{ \gray{ \mathtt{M.V = P \times n + \frac{P \times n(n + 1)}{2 \times 12} \times \frac{r}{100} }}}}$

where,

M.V is the maturity value,

P is the principal amount,

n is the number of months,

r is the rate of interest .

$\underline{ \underline{{ \huge{ \mathtt{S}}} \mathtt{OLUTION - }}}$

$\mathtt{M.V \: = P \times n + \frac{P \times n(n + 1)}{2 \times 12} \times \frac{r}{100} } \\ \\ \mathtt{ \implies{8092 = 140 \times 48 + \frac{140 \times 48(48 + 1)}{2 \times 12} \times \frac{r }{100} }} \\ \\ \mathtt{ \implies{8092 = 6720 + \frac{ \cancel{14} ^{7} \cancel{0} \times \cancel{48} { ^{ \cancel{4}} }^{ 2} \times 49}{ \cancel{2} \times \cancel{12}} \times \frac{r}{ \cancel{10} ^{5} \cancel{0}} }} \\ \\ \mathtt{ \implies{8092 = 6720 + \frac{686 \: r}{5} }} \\ \\ \mathtt{ \implies{8092 - 6720 = \frac{686 \: r}{5} }} \\ \\ \mathtt{ \implies{1372 = \frac{686 \: r}{5} }} \\ \\ \mathtt{ \implies{ \frac{ \cancel{1372 } ^{2} \times 5}{ \cancel{686}} = r}} \\ \\ \boxed{ \purple{ \mathtt{ \therefore{r = 10 \: \% \: \: \: ans.}}}}$

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@MissSolitary✌️

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