Physics, asked by Astronautnikhil8217, 1 year ago

Pure Si at 500K has equal number of electron (n_{e}) and hole (n_{h}) concentrations of 1.5 × 10¹⁶ m⁻³. Doping by indium increases v to 4.5 × 10²² m⁻³. The doped semiconductor is of
(a) n–type with electron concentration n_{e}=5\times 10^{22}\ m^{-3}
(b) p–type with electron concentration n_{e}=2.5\times 10^{10}\ m^{-3}
(c) n–type with electron concentration n_{e}=2.5\times 10^{23}\ m^{-3}
(d) p–type having electron concentration n_{e}=5\times 10^{9}\ m^{-3}

Answers

Answered by kameena1
0

HEY .....

HERE'S YOUR....

HIGH RATED GABRU---HARSH

♦️♦️♦️♦️♦️♦️♦️♦️♦️♦️

YOUR ANSWER IS OPTION---D

Answered by Anonymous
0

Hello Friend

The answer of u r question

Option.D

Thank you

Similar questions