Question

pushpa returned a sum of rupees 4800 against some loan at an interest of 4% p.a. for a period of 5 years find the sum borrowed by her​

Answer 1

Answer:

SI= P×R×T/100

SI=4800×4×5/100

SI= 960

I hope it will help you

Answer 2

Principal = P

S.I. = 4800

Rate of Interest = 4%

Time = 5 years

$s.i. \: = \frac{p \times r \times t}{100} \\ 4800 = \frac{p \times 4 \times 5}{100} \\ \frac{4800 \times 100}{4 \times 5} = \: p \\ </strong><strong>\ ₹2400 = p$