Question

Pushpak Express leaves Lucknow at 6 a.m. and 2 hours later another train Bhopal Express leaves Lucknow both train arrive Bhopal at 4 P.M on the same day with the difference between their speeds be 10 km per hour what is the average speeds of both the trains over the entire route

Answer 1

Let speed of 1st train = x kmph
And speed of 2nd train = (x+10kmph)
So,
x*10=(x+10)8
x=40kmph
Required average speed=(2*40*50) (40+50)
=44(4/9)