Math, asked by nadeemmureed19, 3 months ago

PUUIL
) The quadratic equation with roots 23 and 2 - Sis
(A) X-4x+1=0 (B) x2 + 4x + 1 = 0 (C)* - 4x - T=0 (D) x +4x-1=0
(2) + 3x - 6x + 2 is divided by x, then the remainder is
(B) 2
NC) 9
(D) 18
(3) The polynomial (x + 2)(x-4)=5+x' has degree
A) 1
B) 2
C) 4
(D) zero
(4) The solution of equation which does not satisfies the original equation is called
(A) Roots
(B) Factor
(C) Extranous TOOL (D) Both A and B
(5) Ifo is cube root of unity then = ?
(В) 0
(D)
(6) The product of fourth roots of unity is
(B) 0
(D) 2
(7) Ir sum of roots is equal to the product of roots of 2x +les+k=0 then k = ?
A) -
VB)
TE)-1
(D) 2
(8) An equation whieb remains unchanged when x is replaced by is called is called
(A) Simultaneous equation (B) Reciprocal equation (C) Algebraic equation (D Radical equation
(9) Ir roots of ax' + bx +e= 0 are imaginary, then b' - 4ac will be
TA) Zero
= (B) Negative
(C) Positive
(D) Both AadB
(10) ""+" + 1 =?
(A) - 1
(B) O
€1
D3
Subi​

Answers

Answered by farhadkadwaikar
4

Answer:

PUUIL

) The quadratic equation with roots 23 and 2 - Sis

(A) X-4x+1=0 (B) x2 + 4x + 1 = 0 (C)* - 4x - T=0 (D) x +4x-1=0

(2) + 3x - 6x + 2 is divided by x, then the remainder is

(B) 2

NC) 9

(D) 18

(3) The polynomial (x + 2)(x-4)=5+x' has degree

A) 1

B) 2

C) 4

(D) zero

(4) The solution of equation which does not satisfies the original equation is called

(A) Roots

(B) Factor

(C) Extranous TOOL (D) Both A and B

(5) Ifo is cube root of unity then = ?

(В) 0

(D)

(6) The product of fourth roots of unity is

(B) 0

(D) 2

(7) Ir sum of roots is equal to the product of roots of 2x +les+k=0 then k = ?

A) -

VB)

TE)-1

(D) 2

(8) An equation whieb remains unchanged when x is replaced by is called is called

(A) Simultaneous equation (B) Reciprocal equation (C) Algebraic equation (D Radical equation

(9) Ir roots of ax' + bx +e= 0 are imaginary, then b' - 4ac will be

TA) Zero

= (B) Negative

(C) Positive

(D) Both AadB

(10) ""+" + 1 =?

(A) - 1

(B) O

€1

D3

Subi

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