Question

px^2 + 2ax + r = 0

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Answer 1

Answer:

Check explanation

Step-by-step explanation:

-b+-root b^2-4ac/2a

So,

Here b=2a

a=p

c=r

Substituting them in the formula

-2a+-root 4a^2-4pr/2a

-2a+-2 root a^2-pr/2a

2(-a+-root a^2-pr)/2a

So, - a+-root a^2-pr/a

Hence the roots are

-a+root a^2-pr/a

-a-root a^2-pr/a

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Hope it helps