px^2 + 2ax + r = 0
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1
Answer:
Check explanation
Step-by-step explanation:
-b+-root b^2-4ac/2a
So,
Here b=2a
a=p
c=r
Substituting them in the formula
-2a+-root 4a^2-4pr/2a
-2a+-2 root a^2-pr/2a
2(-a+-root a^2-pr)/2a
So, - a+-root a^2-pr/a
Hence the roots are
-a+root a^2-pr/a
-a-root a^2-pr/a
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Hope it helps
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