Question

pythagoras theorem AC=13 , AB=7 , BC=?
pythagoras theorem AC=? , AB= 6 , BC=4
pythagoras theorem AC =12 , AB=? , BC=3​

Answer 1

Answer:

I) BC = √(AC^2-AB^2)

=√(169-49)

= √120=2√30

II)AC=√(AB^2+BC^2)

=√(36+16)

=√52

III)AB=√(AC^2-BC^2)

=√(144-9)

=√135

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