Pythagoras triplet of 98
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A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c).
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we know,
2m, m²+1, m²-1
2m= 98
m= 98/2
m= 49
m²+1
=49²+1
=2401+1
=2402
m²-1
=49²-1
=2401-1
=2400
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