Question

Pythagorean triplet whos smallest number is 8

Answer 1

We know that 2m,m^2-1 and m^2+1 form a Pythagorean triplet
2m = 8
m = 8/2=4
m^2-1=4^2-1
= 16-1
= 15
m^2 +1 = 4^2 + 1
= 16 + 1
= 17
8,15 and 17 form a Pythagorean triplet