Question

Pythagorean Triplet whose one no is 8 with method

Answer 1

If one number is 8, then we can take other 2 numbers as 6 and 10
So by Pythagoras Theorem
H^2=B^2+P^2
10^2=6^2+8^2
100=36+64
100=100
As LHS= RHS
So the triplet (6,8,10) is forming Pythagoras

Answer 2

Pythagorean Triplet are in form of:

2 n  , n² + 1 and n²- 1

Here,

2n = 8

n = 4

So

n²+1 = 4²+1 = 17

n²-1 = 4²-1 = 15

• Pythagorean Triplet = 8 , 15 and 17.