Question

Q. 1. 2 cubes each of volume 64 cm² are joined
end to end. Find the surface area of the resulting
cuboid.​

Answer 1

Answer:

$side \: of \: cube = \sqrt[3]{64} = 4 \: cm$

$cuboid \: dimensions \\ length = 8cm \\ breadth=4 \: cm\\ height = 4 \: cm$

$surface \: area \: of \: cuboid = 2lb + 2bh + 2lh$

$surface \: area \: of \: cuboid = 2 \times 8 \times 4 + 2 \times 4 \times 4 + 2 \times 4 \times 8$

$surface \: area \: of \: cuboid = 64 + 32 + 64 = 160 \: cm$