Question

Q-1) ab (a -b+c )+bc (2a-2b+2c)+ca (3a-3b+3c)

Q-2) (2x-3)²-8x+12 .

Answer 1

Q - 1

ab ( a - b + c ) + bc ( 2a - 2b + 2c ) + ca ( 3a - 3b + 3c )

= ab ( a - b + c ) + 2bc ( a - b + c ) + 3ca ( a - b + c )

= ( a - b + c ) ( ab + 2bc + 3ac )

[ Note : Take 2 as a common in second terms and 3 in third term ]

Q - 2

( 2x - 3 )^2 - 8x + 12

= ( 2x )^2 + 2 ( 2x )( - 3 ) + ( - 3 )^2 - 8x + 12

= 4x^2 - 12x + 9 - 8x + 12

= 4x^2 - 20x + 21

= 4x^2 - 6x - 14x + 21

= 2x ( 2x - 3 ) - 7 ( 2x - 3 )

= ( 2x - 3 )( 2x - 7 )

✌

Answer 2

HELLO DEAR,


ab (a -b+c )+bc (2a-2b+2c)+ca (3a-3b+3c)

=> ab (a -b+c )+bc×2(a-b+c)+ca×3(a-
b+c)

=> (a-b+c)(ab+2bc+3ca)

[(a-b+c) common in all)]



---------------------(2)-------------------------


(2x-3)²-8x+12

=> (2x)²+(3)²-2×(2x)×(3) -8x +12

=> 4x²+9 - 12x - 8x + 12

=> 4x² - 20x +21

=> 4x² - 6x - 14x + 21

=> 2x(2x-3) -7(2x-3)

=> (2x-3) (2x-7)




I HOPE ITS HELP YOU DEAR,
THANKS