Question

Q.1 if a=1 and b=2, find the value of (-6ab)×(3a^2)​

Answer 1

Step-by-step explanation:

substitute the values a=1 and b=2

= -6(1)(2) x 3(1)^2

= -12×3

= -36

Hope this helps

Answer 2

(-6×1×2)×(3×1×1)

(-12)×(3)

-36