Q.1 If a hexagon ABCDEF circumscribe a circle, prove that
AB + CD + EF = BC + DE + FA
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Answer:
since, tangents drawn from an external point to a circle are equal. Therefore,
AM=AR
BM=BN
OC=NC
OD=DP
QE=PE
FQ=RQ
add them
AM+BM+OC+OD+QE+FQ=AR+BN+NC+DP+PE+RQ
AB+CD+EF=BC+DE+FA
Hence proved.
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