Q.1 Prove that the madians of an equilateral triangle are equal.
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Let ABC be the given equilateral △.
Then the things that we ,
∠.A=60°
∠.B=60°
∠C=60°
And ,
AB=BC=AC
and let AE , BD and CF be the medians.
we know that
A median divides a side into two equal parts.
AB=BC=AC
AF+BF=BE+CE=AD+CD
2AF=2BE=2AD
AF=BE=AD
therefore,
AF=BF=BE=CE=AD=CD............................(1)
In △ AEC and △ABD we have.
AC=AB
∠.C=∠.A
EC=AD (from eq..1)
By SAS congruency criterion we get,
△ AEC congruent to △ABD.
By CPCT we get,
AE=BD..........................................................(2)
Similarly we can prove,
△ ABD congruent △ AFC
Then,
BD=CF..........................................................(3)
By eq2 and eq3 we get,
AE=CF=BD
Hence,
it is proved that the medians of equilateral triangle are equal
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hope it helps..thanks
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