Q 1. Solve the following linear pair
of equations graphically,
2x+3y_8=0
X_2y+3=0 Also find the
coordinates of the triangle formed
by these two lines and x axis. Find
the area of the triangle also.
Answers
Answer:
Answer:
EXPLANATION.
Linear pair of equation graphically.
(a) = 2x + 3y - 8 = 0.
(b) = x - 2y + 3 = 0.
From equation (1) we get,
(a) = 2x + 3y = 8.
put x = 1 in equation, we get.
⇒ 2(1) + 3y = 8.
⇒ 2 + 3y = 8
⇒ 3y = 8 - 2.
⇒ 3y = 6.
⇒ y = 2.
Co-ordinate = (1,2).
Put x = 4 in equation, we get.
⇒ 2(4) + 3y = 8.
⇒ 8 + 3y = 8.
⇒ 3y = 8 - 9.
⇒ 3y = 0.
⇒ y = 0.
Co-ordinate = (4,0).
(b) = x - 2y = -3.
put x = 1 in equation, we get.
⇒ 1 - 2y = -3.
⇒ -2y = -3 - 1.
⇒ -2y = -4.
⇒ y = 2.
Co-ordinate = ( 1,2).
put x = -3 in equation, we get.
⇒ - 3 - 2y = -3.
⇒ -2y = 0.
⇒ y = 0.
Co-ordinate = (-3,0).
To find areas of the triangle.
Area of Δ = 1/2 X B X H.
Area of (ΔAOC) = 1/2 X 7 X 2.
Area of (ΔAOC) = 7 sq. units.
Answer:
7sq units please mark the answer as the brainliest and verified