Math, asked by sindusarode6502, 1 year ago

Q.1. The dimensions of a rectangular box are in the ratio of 2:3:4 and the difference between the cost of covering it with the sheet of paper at the rates of Rs.8 and Rs 9.50 per metre square is Rs.1248. Find the dimensions of the box.

Guyss the answer is 8m,12m,16m ..... can anyone explain this question by doing stepwise calculations with statements

Answers

Answered by Aasthakatheriya1
4
hello...

Since the dimensions are in the ratio 2 : 3 : 4. So let it be 2x, 3x and 4x

Curved Surface Area of the Cuboid = 2(lb + bh + lh)

Curved Surface Area of the Cuboid = 2(2x*3x + 3x*4x + 2x*4x)

= 2(6x2 + 12x2 + 8x2)

= 2(26x2) = 2 * 26x2 

= 52x2 m2

Cost of papering at the rate of Rs. 9.50 per m2 = Rs. (52x2 * 9.50)

Cost of papering at the rate of Rs. 8 per m2 = Rs. (52x2 * 8)

Differenc between the costs = Rs. (52x2 * 9.50) - Rs. (52x2 * 8)

= 52x2 (9.50 - 8) = Rs.1248

52x2 * 1.50 = Rs.1248

x2 = 1248 / (1.50 * 52) = 16

or, x = sqrt.(16) = 4m

DImensions of the Box are 

Length = 2x = 2*4m = 8m

Breadth = 3x = 3*4m = 12m

Height = 4x = 4*4m = 16m.
I hope it help you ☺️☺️

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