Q.1) The length and breadth of a rectangular park are in the ratio 5:2. A 2.5 meters wide path running all around the outside the park has an area 305m2. Find the dimensions of the park.
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Given that area of the park be 305m^2.
Let the length of the park be 5x m and breadth be 2x m.
Therefore,
Area of the rectangular park = (5x) x (2x)
= 10x^2 m^2
Width of the path = 2.5 m
From the figure,
Outer length PQ = 5x m + 2.5 m + 2.5 m
= (5x + 5) m
Outer breadth QR = 2x + 2.5 m + 2.5 m
= (2x + 5) m
Area of PQRS = (5x + 5) m x (2x + 5) m
= (10x2 + 25x + 10x + 25) m^2
= (10x2 + 35x + 25) m^2
Area of the path = [(10x^2 + 35x + 25) – 10x^2] m^2
By solving above equation we get
305 = 35x + 25
305 – 25 = 35x
280 = 35x
x = 280/35 = 8
Therefore,
Length of the park = 5x
= 5 x 8 = 40 m
Breadth of the park = 2x
= 2 x 8 = 16 m
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this is the correct answer
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