Q-1)Total momentum of 2 bodies remain uncharged before and after the collision .Justify this statement....
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suppose an object A has mass m1 and it's initial velocity is u1. An object B has mass m2 and initial velocity u2
According to the formula for momentum, the initial momentum of A is m1u1 and that of B is m2u2
suppose these two objects collide. Let the force on A due to B be F1. This force will cause acceleration in A and it's velocity become V1
momentum of A after collision=M1V1
According to Newton's third law of motion, A also exerts an equal force on B but in the opposite direction. This will cause a change in the momentum ofB. It's velocity after collision is V2
momentum of B after collision=M2V2.If F2 force that acts on object B
F2=-F1
M2A2=-M1A1
M2×(V2-U2) /t=M1×(V1-U1) /t
M2(V2-U2) =M1(V1-U1)
M2V2-M2U2=M1V1-M1U1
M2V2+M1V1=M2U2+M1U1
According to the formula for momentum, the initial momentum of A is m1u1 and that of B is m2u2
suppose these two objects collide. Let the force on A due to B be F1. This force will cause acceleration in A and it's velocity become V1
momentum of A after collision=M1V1
According to Newton's third law of motion, A also exerts an equal force on B but in the opposite direction. This will cause a change in the momentum ofB. It's velocity after collision is V2
momentum of B after collision=M2V2.If F2 force that acts on object B
F2=-F1
M2A2=-M1A1
M2×(V2-U2) /t=M1×(V1-U1) /t
M2(V2-U2) =M1(V1-U1)
M2V2-M2U2=M1V1-M1U1
M2V2+M1V1=M2U2+M1U1
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