Q.10- A body reaches ground in time T when dropped from height h, what is the time taken by the body
if it is dropped from height 2h?
(a) 2 T
(b) (V2 - 1)T
(c) V2T
(c) T/v2
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Explanation:
takes time “T” to reach the ground then,
H = 0.5gT²
T = √(2H/g)
If it takes time “t” to travel first half of the journey then,
0.5H = 0.5gt²
H = gt²
t = √(H/g)
Time taken to cover second half of the journey is = T - t
= √(2H/g) - √(H/g)
= √(H/g)×(√(2) - 1)
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