Question

Q. 10. In Fig. PQ XY EXZ 8cm. ZP = 2 cm, Y2 = 16 cm, find ZQ​

Answer 1

Given :  PQ || XY

XZ is 8 cm, ZP is 2 cm, YZ is 16 cm,

To Find  : ZQ

Solution:

PQ || XY

=> ∠X = ∠P  & ∠Y = ∠Q  ( corresponding angles)

∠Z = ∠Z is common

Hence Δ PQZ ≈ Δ XYZ  (AAA)

Similar Triangles: corresponding angles are congruent and the corresponding sides are proportional

=>  ZP/XZ = ZQ/YZ

=>  2 / 8  =  ZQ / 16

=> 1/ 4 =  ZQ / 16

=> 4 = ZQ

ZQ = 4cm

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