Question

Q.10 The dipole moment of the ammonia molecule is 1.48D.
The length of the dipole is -

(A)3.08x10-11m
(B) 5 x 102m
(C)308 m
(D) None​

Answer 1

Answer:

option A is correct......

Answer 2

The dipole moment of the ammonia molecule is 1.48 D.  The length of the dipole is $3.09 \times 10^{-13} m$.

Explanation:

We known that relation between dipole moment and distance or length of dipole is as follows.

            $\mu = q \times r$

where,   $\mu$ = dipole moment

               q = charge on the atoms = $1.6 \times 10^{-19}$

                r = distance between the dipoles

It is known that,

             1 Debye = $3.35 \times 10^{-30} cm$      

or,       1.48 Debye = $1.48 \times 3.35 \times 10^{-30} cm$

                              = $4.958 \times 10^{-30} cm$

Now, putting the values into the above formula as follows.

              $\mu = q \times r$

    $4.958 \times 10^{-30} cm = 1.6 \times 10^{-19} \times r$  

           r = $3.09 \times 10^{-11}$ cm

or,          = $3.09 \times 10^{-11} cm \times 0.01 m/cm$

             = $3.09 \times 10^{-13} m$

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