Math, asked by owais536, 6 months ago

Q.10 The
measures of the angles of
of a
triangle are in A.P. and the greatest is
5 times the smallest (least). Find the
angles in degree and radian.​

Answers

Answered by Anonymous
3

Answer:

Angles respectively will be 20 ° , 60° and 100°

Step-by-step explanation:

MOST IMPORTANT PROPERTY TO BE USED HERE IS THAT THE SUM OF ANGLES OF A TRIANGLE IS 180° .

NOW , considering it to be in A.P . let us assume first angle to be equal to "a" . Then , the third and the largest is 5a . Now , let the second angle be equal to a+d . Using the properties of an AP , we get that , (a+d - a ) = 5a - (a +d)

This gives , d = 4a -d ------ (1)

Also , a + (4a-d) + a + 5a = 180

11a - d = 180 --------- (2)

From 1 , d = 2a .

putting this in 2 .

a = 20 °.

d = 40°

So angles respectively will be 20 ° , 60° and 100° . Now you can convert the same into radians . Hence will be your answer .

Answered by shubhamkh9560
1

Answer:

Step-by-step explanation:

MOST IMPORTANT PROPERTY TO BE USED HERE IS THAT THE SUM OF ANGLES OF A TRIANGLE IS 180° .

NOW , considering it to be in A.P . let us assume first angle to be equal to "a" . Then , the third and the largest is 5a . Now , let the second angle be equal to a+d . Using the properties of an AP , we get that , (a+d - a ) = 5a - (a +d)

This gives , d = 4a -d ------ (1)

Also , a + (4a-d) + a + 5a = 180

11a - d = 180 --------- (2)

From 1 , d = 2a .

putting this in 2 .

a = 20 °.

d = 40°

So angles respectively will be 20 ° , 60° and 100° . Now you can convert the same into radians . Hence will be your answer .

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