Q-11. An object starting from rest is moving with a constant acceleration. It travels a distance of 600
min 40 seconds. Find its acceleration and also find the force acting on it if the mass of the object is
40kg
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Answer:
a=0.75 m/s^2 F=30N
Explanation:
simply apply Newton's second equation of motion
s=ut+1/2at^2
it's starting from rest so initial velocity u=0m/s
t= 40s so a can be calculated
600=0×t+1/2a ×40^2
1600a=1200
a=0.75m/s^2
and force can be calculated as
F=ma
F=40×0.75=30N
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