Q -11 Please help in this question
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Solution is in the attachment.....
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Total no. of possible outcomes=36
i) No. of favourable outcomes= 6
P(getting a doublet)= 6/36=1/6
ii)No. of favourable outcomes=3
P(getting a sum 10 of the numbers on the two dice)=3/36=1/12
i) No. of favourable outcomes= 6
P(getting a doublet)= 6/36=1/6
ii)No. of favourable outcomes=3
P(getting a sum 10 of the numbers on the two dice)=3/36=1/12
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