Question

q 11 pls pls pls answer​

Answer 1

${x}^{2} - 5x + k$

here,

$\alpha - \beta = 1 \\ \alpha = 1 + \beta$

so,sum of zeroes=

$\frac{ - b}{a}$

so,

$\alpha + \beta = - (\frac{ - 5}{1} ) \\ \beta + 1 + \beta = + 5 \\ 2 \beta + 1 = + 5 \\ 2\beta = 5 - 1 \\ \beta = \frac{4}{2} \: \\ \beta = 2$

but,

$\alpha = 1 + \beta$

so,

$\alpha = 1 + 2 \\ \alpha = 3$

so zeroes are

$\alpha = 3 \\ \beta = 2$

now product of zeroes=

$\frac{c}{a}$

so,

$\alpha \times \beta = \frac{k}{1} \\ 3 \times 2 = k \\ k = 6$

so , the value of k is 6

*PLS. MARK BRAINLIEST IF CORRECT*