Q.11) What is the magnitude of a point charge chosen so that the electric field 50cm away has magnitude 2.0N/C?
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Electric field,E= kq/r²
{ r is the distance from the charge and r= 0.5m}
or 2 = kq/(0.5)²
or q = 2×(0.5)²/ 9×10^9 = 0.055 nC
{ r is the distance from the charge and r= 0.5m}
or 2 = kq/(0.5)²
or q = 2×(0.5)²/ 9×10^9 = 0.055 nC
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