Question

Q.12 An ice cube is kept on an
inclined plane of angle 30º.
Coefficient of kinetic friction
between block and inclined plane is 11
√3. What is the acceleration of the
block? *​

Answer 1

Answer:

Ice cube is kept on inclined plane of angle 30

∘

and kinetic friction is

3

1

.

Now balancing forces

mgsin30−μ

k

mg=ma

gsin30−μ

k

g=a

a=(sin30−μ

k

)g

a=(

2

1

−

3

1

)g

a=(

2

3

3

−1

)g

a=0.2113×9.8

a=2.07m/s

2

a≈2m/s

2

Thus acceleration of the block is 2m/s

2

I HOPE IT HELPS U

Answer 2

Answer:

Ice cube is kept on inclined plane of angle 30

∘

and kinetic friction is

3

1

.

Now balancing forces

mgsin30−μ

k

mg=ma

gsin30−μ

k

g=a

a=(sin30−μ

k

)g

a=(

2

1

−

3

1

)g

a=(

2

3

3

−1

)g

a=0.2113×9.8

a=2.07m/s

2

a≈2m/s

2

Thus acceleration of the block is 2m/s

2

.