Q.12 An ice cube is kept on an
inclined plane of angle 30º.
Coefficient of kinetic friction
between block and inclined plane is 11
√3. What is the acceleration of the
block? *
Answers
Answered by
1
Answer:
Ice cube is kept on inclined plane of angle 30
∘
and kinetic friction is
3
1
.
Now balancing forces
mgsin30−μ
k
mg=ma
gsin30−μ
k
g=a
a=(sin30−μ
k
)g
a=(
2
1
−
3
1
)g
a=(
2
3
3
−1
)g
a=0.2113×9.8
a=2.07m/s
2
a≈2m/s
2
Thus acceleration of the block is 2m/s
2
I HOPE IT HELPS U
Answered by
0
Answer:
Ice cube is kept on inclined plane of angle 30
∘
and kinetic friction is
3
1
.
Now balancing forces
mgsin30−μ
k
mg=ma
gsin30−μ
k
g=a
a=(sin30−μ
k
)g
a=(
2
1
−
3
1
)g
a=(
2
3
3
−1
)g
a=0.2113×9.8
a=2.07m/s
2
a≈2m/s
2
Thus acceleration of the block is 2m/s
2
.
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