Q-12. Find the probability that a number selected at random from the numbers 1, 2, 3, ...., 35 is a
(i) prime number
(ii) multiple of 7
(iii) a multiple of 3 or 5
(iv) divisible by 2 and 3 both (v)odd Number
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Answers
Answer:
1. 11/35
2. 4/35
3. 16/35
4. 5/35=1/7
5. 18/35
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Total no. of possible outcomes = 35 {1, 2, 3, …. 35}
(i) E ⟶ event of getting a prime no.
No. of favourable outcomes = 11 {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31}
Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 11/35
(ii) E ⟶ event of getting no. which is multiple of 7
No. of favourable outcomes = 5 {7, 14, 21, 28, 35}
P(E) = 5/35 = 1/7
(iii) E ⟶ event of getting no which is multiple of 3 or 5
No. of favourable outcomes = 16 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 5, 10, 20, 25, 35}
P(E) = 16/35
(iv) E ⟶ event of getting no which is divisible by both 2 and 3
No. of favourable outcomes = 5 {6, 12, 18, 24, 30}
P(E) = 5/35 = 1/7
(v) E ⟶ event of getting an odd numbers
No. of favourable outcomes = 18 {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35}
P(E) = 18/35